In the image below, a worker is pushing a crate with a mass of 25 kg up a ramp at a constant rate. Ignoring friction, how much force must the worker apply so that the crate continues to move at the same speed? (Recall that g = 9.8 m/s2)

A. 35.3N
B. 83.8N
C. 50.2N
D. 16.2N

The image is missing, so i have attached it.

B. 83.8N

Explanation:

The mass of the worker is 25 kg

From the image, the angle of the ramp is 20°

To find the force that the worker must apply to make the crate continue to move at the same speed, we will use the formula;

F = mg sin θ

F = 25 × 9.8 × sin 20

F ≈ 83.8 N

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

When you go to ask a qustion there will be a picture of a paper clip looking thing and then it will pop up your files and you click on the imajes and then you up load it