What is the average velocity of atoms in 1.00 mol of neon (a monatomic gas) at 2°C? For m, use 0.0202 kg.

The average Velocity of the atoms =582.73m/s

Explanation:

Given

Mole of neon gas = 1.00 mol

Temperature = 2°C changing to Kelvin becomes

2°C + 273.15 = 275.15K

Mass = 0.0202 kg

Using the equation that connects the Average kinetic energy with ideal gas equation we have that

Kinetic energy=3/2 nRt

1/2(mv^2) = 3/2 nRt

Where

M = mass,

V = volume.

R = gas constant(8.31 jK-1 mol-1,

t = temperature in Kelvin,

n = number of moles

Putting our known values, we have that

1/2(0.0202 × v^2) = 3/2 (1 × 8.31 × 275.15)

0.0101 v^2 = 3,429.745

v^2 = 3429.745 / 0.0101

v^2 = 339,578.713

v = √339578.713

v = 582.73m/s

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the temperature in kelvin of 2.0 dm3 of an ideal gas is doubled and its pressure is increased by a factor of four. what is the final volume of the gas