A positive charged particle and another positively charged particle are 0.5m from each other and have a force of 16N between each of them. If the particles are moved so that they are now 1M from each other (doubling their distance), what is the new force between them? Why?

Aparticle moves in the xy plane with constant acceleration. at time zero, the particle is at x = 6 m, y = 8.5 m, and has velocity ~vo = (9 m/s) ˆı + (−2.5 m/s) ˆ . the acceleration is given by ~a = (4.5 m/s 2 ) ˆı + (3 m/s 2 ) ˆ . what is the x component of velocity after 3.5 s? answer in units of m/s.