Please answer fast A 50 kg boy jumps off the front of a 1.5 kg skateboard moving forward. Find the skateboard's velocity
immediately after the boy jumps, assuming that the skateboard's initial velocity is 3.5 m/s and the boy's
velocity when jumping off the front is 5 m/s?

The speed is 1.35 m/s

Explanation:

(m1+m2) vi= m1+m2v2

(50+1.5) (3.5)=50 (5+v2) +1.5 v2

180.25= 250+ 51.5 v2

180.25- 250+ 51.5 v2

-69.75= 51.5 v2

v2= -1.35 m

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts