Acharged paint is spread in a very thin uniform layer over the surface of a plastic sphere of diameter 10.0cm , giving it a charge of -15.0_c .

a: find the electric field just inside the paint layer.
b: find the electric field just outside the paint layer.
c: find the electric field 6.00cm outside the surface of the paint layer.

(1/4πϵ0)q/r2=(9∗109)∗(−15)/(0.06∗0.06)=3.75∗1013newton/coloumEdA=qenclosedϵ0 EA=qenclosedϵ0 E(4πr2)=qenclosedϵ0 E=qenclosed(4πr2)ϵ0 E=−15X10−6C(4π(5X10−2+6X10−2)2)ϵ0roadjester  3 years agoI converted the radius to meters You want the electric field 6cm outside of the sphere so the radius is 5 cm (half of the diameter of the sphere) plus the 6cm so the net radius is actually 11c

It should be d if not then c

Simple harmonic motion wind energy circulation best answer from the choices