Two objects with masses my and m2 are hung by a string through a pulley. In this system, mi is greater than m2, while the string and the pulley are massless. Initially, both masses are held at rest at the same height.
What will happen when the objects are released?
A)
mi will move upward with an acceleration of
(m1 - m2)
9.
(m1+
m2)
B)
m2 will move upward with an acceleration of
(m1 + m)
9.
(m1-m2)
m1 will move downward with an acceleration of
(m1 - m2
9.
(m1+ m2)
C)
D)
m2 will move downward with an acceleration of
(mi + m2)
9.
(m1-m2)

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever

the answer would be a

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .