A person with a mass of 60 kg stands on a scale in an elevator. What will the scale read (apparent weight or normal force) when the elevator is accelerating downward at 1 m/s2?

660 N

Explanation:

From the question,

When an Elevator moves downward,

R = m(g+a) Equation 1

Where R = apparent weight of the person, m = mass of the person, g = accleration due to gravity, a = acceleration of the elevator

Given: m = 60 kg, g = 10 m/s², a = 1 m/s²

Substitute these values into equation 1

R = 60(10+1)

R = 60(11)

R = 660 N.

Hence the apparent weight of the person is 660 N

i think its c if i'm wrong

e/c, where e is its total energy