A diver of mass 65 kg takes off from the 10 m platform from a standing position by jumping upwards with a (near) vertical speed of 2.0 ms-1. Use 2 methods (uniform motion equations and the principle of conservation of energy) to check the accuracy of the statement at the beginning of the passage that a diver jumping from the high platform will hit the water at 30 mph?

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

the answer is b i think

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s