A 2.0-kg mass swings at the end of a light string (length = 3.0 m). Its speed at the lowest point on its circular path is 6.0 m/s. What is its kinetic energy at an
instant when the string makes an angle of 50° with the vertical?

Kinetic Energy = 36 Joules

Explanation:

Given =

Mass = 2kg

Velocity = 6m/s

Solution =

Kinetic Energy = 1/2 × mv²

Kinetic Energy = 1/2 × 2 × 6 × 6

Kinetic Energy = 36 Joules

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