Student builds a simple circuit with a single resistor with resistance R and measures an electric potential difference ΔV across the resistor. Then, the student replaces the resistor with a new one of resistance 2R and keeps the electric potential difference the same. What is the current (I2) through the new circuit in terms of the original current​(I1)?              6mks ​

 i₂ = ½ i₁

Explanation:

Let's write ohm's law for the first statement

           V = i₁ R

            i₁ = V / R

tells us that we change the resistance to R '= 2R

let's write ohm's law

            V = i₂ R’

indicates that V remains constant

            i₂ = V / R '

            i₂ = V / 2R

            i₂ = ½ V/R

we substitute

            i₂ = ½ i₁

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