If an electron is accelerated from rest through a potential difference of 9.9 kV, what is its resulting speed

v = 5.9 x 10⁷ m/s

Explanation:

The kinetic energy of the electron in terms of potential difference is given as:

--------------- equation (1)

where,

e = charge on electron = 1.6 x 10⁻¹⁹ C

V = Potential Difference = 9.9 KV = 9900 Volts

The kinetic energy in general is given as:

--------- equation (2)

where,

m = mass of electron = 9.1 x 10⁻³¹ kg

v = speed of electron = ?

Therefore, comparing equation (1) and equation (2), we get:

v = 5.9 x 10⁷ m/s

at positions a, g kinetic energy is maximum.

at position d, potential energy is maximum.

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