Heat engine uses one mole of air in ideal state as the working fluid operates between 350 K and 600 K temperatures according to Carnot cycle. Initially, the pressure is 10 atm. After the isothermal expansion step, the pressure has been reduced to 5 atm and after the isothermal compression step, the pressure is 3 atm. Calculate the thermal efficiency of this engine and calculate the work done in each step in this cycle. Given that for air, the ratio (= 1.4).​

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j