If 59.1 g of pure metal uses 890.9 j of energy to heat it from 26.1 c to 59.6 c, identify the metal

The metal is iron.

Explanation:

We have 59.1 grams of a given metal.

We need 890.9 joules of energy to heat the metal from 26.1°C to 59.6°C

First, we need to see the net increase in temperature, which is equal to the difference between the final temperature and the initial temperature.

ΔT = 59.6°C - 26.1°C = 33.5°C

Now we can find the specific heat, which is calculated as:

c = Ε/(ΔT*m)

Where:

E = energy given to the material = 890.9 J

m = mass of the material = 59.1 gr

ΔT = change in temperature = 33.5°C

Replacing these in the above equation we get:

c = 890.9 J/(33.5°C*59.1 gr) = 0.45 J/(gr*°C)

Now we need to look at a table of specific heats and see which metal has this specific heat.

We can see that iron is the best match, so we can assume that the metal is iron.