Physics, 22.02.2021 02:20 algahimnada
A student passed a current of 0.6 A through copper sulfate solution for 300 s Calculate the charge flow through the solution.
Answers: 2
Physics, 22.06.2019 03:00
Which of the following is not a part of the respiratory system? a. pharynx b. trachea c. pancreas d. larynx
Answers: 1
Physics, 22.06.2019 07:50
Calculate the ratio of h+ ions to oh– ions at a ph = 6. find the concentration of h+ ions to oh– ions listed in table b of your student guide. then divide the h+ concentration by the oh– concentration. record this calculated ratio in table a of your student guide. compare your approximated and calculated ratios of h+ ions to oh– ions at a ph = 6. are they the same? why or why not? record your explanation in table a. what is the concentration of h+ ions at a ph = 6? mol/l what is the concentration of oh– ions at a ph = 6? mol/l what is the ratio of h+ ions to oh– ions at a ph = 6? : 1
Answers: 1
Physics, 22.06.2019 11:00
Although longitudinal waves can travel through all media types what is the disadvantage of this type of wave transmission? a) he efficiency of he wave transmission is greatly diminished as the media becomes less dense b) the oscillation of one set of particles has a huge impact on neighboring particles c) particles become too close together as they bump into each other making it more likely to hit other particles down the line
Answers: 2
Physics, 22.06.2019 21:20
An electron is ejected into a horizontal uniform e⃗ field at a parallel horizontal velocity of v0. assume the electron's initial position x0, initial velocity v0, time t, magnitude of electric field e, electron's mass m, and the magnitude of the electron's charge |e|. ignore the force that earth exerts on the electron. assume the e⃗ field is in the same direction as the initial velocity. part a define the equation for the electron's velocity. express your answer in terms of the variables v0, |e|, t, e, and m.
Answers: 3
A student passed a current of 0.6 A through copper sulfate solution for 300 s
Calculate the charge...
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