WILL MARK BRAINLIEST FOR THE CORRECT ANSWER AND EXPLANATION When traveling at top speed, a roller coaster train with a mass of 12,000 kg has a velocity of 30 m/s. The kinetic energy of the train at top speed is
J.
Given this kinetic energy, what is the tallest hill this roller coaster train can reach the top of?
The train can climb a hill that is
m. high.

Kinetic energy = 5400000 J

Height, h = 45.91 m

Explanation:

It is given that,

Mass of the roller coaster train, m = 12,000 kg

Velocity of the train, v = 30 m/s

Kinetic energy is given by :

KE=\dfrac{1}{2}mv^2KE=

2

1

mv

2

KE=\dfrac{1}{2}\times 12000\ kg\times (30\ m/s)^2KE=

2

1

×12000 kg×(30 m/s)

2

KE=5400000\ JKE=5400000 J

So, the kinetic energy of the train at the top speed is 5400000 J.

For height

According to law of conservation of energy :

PE_i+KE_i=PE_f+KE_fPE

i

+KE

i

=PE

f

+KE

f

0+5400000\ J=mgh+00+5400000 J=mgh+0

5400000\ J=mgh5400000 J=mgh

h is the height.

5400000\ J=12000\ kg\times 9.8\ m/s^2\times h5400000 J=12000 kg×9.8 m/s

2

×h

h=45.91\ mh=45.91 m

Hence, this is the required solution.

1 the 4 is sig

the components of a vector are the parts of the vectors that are to each other.

b perpendicular