The electric field from two charges in the plane of the paper is represented by the dashed lines and arrows below. Select a response for each statement below. (Use 'North' towards top of page, and 'East' to the right)

The magnitude of the E-field at Ris than at M.

The force on a (+) test charge at P is zero.

The magnitude of the charge on the left is that on the right.

The force on a (+) test charge at L is directed

The force on a (-) test charge at J is directed

The force on a (-) test charge at N is directed

The sign of the charge on the right is negative.

a) electric field at point P must be zero

b) harged must be positive

c) force ais in the direction of the electric field

d)  force is in the opposite direction to the electric field

e)  force is in the opposite direction to the field

Explanation:

After reading your exercise, it is unfortunate that the diagram did not come out, but we are going to answer the questions in general.

a) force on a charge (+) is zero

this implies that the electric field at point P must be zero

        F = q E

b) the magnitude of the charge on the left is on the right

this indicates that the charged must be positive since the lines must exit the charge

c) force on load directed towards (direction not indicated)

since the charge is positive the force at point L is in the direction of the electric field at this point

d) force on test load (-) does not indicate direction

The force on a negative charge is in the opposite direction to the electric field at point J

e) Force on a test load (-) at point N

the force is in the opposite direction to the field at point N

the answer is kevlar