2. A positive charge of 3x10-7 is located in a field of 27N/C directed toward the south. What is the force acting on the charge? 3. A positive test charge of 5x10-6Cis in an electric field that exerts a force of 2x10-4N on it.
What is the magnitude of the electric field at the location of the test charge?

Explanation:

(1) Given that,

A charge,

Electric field, E = 27 N/C

We need to find the force acting on the charge. The force on the charge is given by :

So, the force acting on the charge is

(b) Charge,

Force,

Let E be the electric field.

So, the electric field is 40 N/C.

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