A circular-shaped object of mass 6 kg has an inner radius of 11 cm and an outer radius of 29 cm. Three forces (acting perpendicular to the axis of rotation) of magnitudes 12 N, 28 N, and 13 N act on the object, as shown. The force of magnitude 28 N acts 26◦ below the horizontal. Find the magnitude of the net torque on the wheel about the axle through the center of the object.
Answerinunitsof N·m.

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initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.