After a long day of driving you take a late-night swim in a motel swimming pool. When you go to your room, you realize that you have lost your room key in the pool. You borrow a powerful flashlight and walk around the pool, shining the light into it. The light shines on the key, which is lying on the bottom of the pool, when the flashlight is held 1.2 m above the water surface and is directed at the surface a horizontal distance of 1.5 m from the edge (Fig. P33.44). If the water here is 4.0 m deep, how far is the key from the edge of the pool

Total length of pool meter

Explanation:

The image for the question is attached for better understanding

degree

Using the Snell’s law –

Total length of pool meter

Explanation:

i is angle of incidence and r is angle of refraction .

Tan i = 1.5 / 1.2 = 1.25

i = 51.34⁰

refractive index of water = 1.33

sin i / sinr = 1.33

sin 51.34 / sin r = 1.33

sinr = .78 / 1.33 = .5864

r = 36⁰

From the figure given ,

AB / AP = Tan 36

AB = AP tan 36 = 4 x tan 36 = 2.9 m

D = OA + AB

= 1.5 + 2.9

= 4.4 M

Distance of key from edge = 4.4 m .

Idk just need points

Distance covered = speed x timethe distance traveled going against the stream = distance traveled with the stream.therefore it is the speed and the time that are the variables.as he travels the same distance both ways, speed x time is the same for each way.going upstream his speed is 4 kph; going downstream his speed is 6 kph.therefore we have two simultaneous equations: time upstream x 4 = time downstream x 6time upstream + time downstream = 60 minutestherefore we have the equation: time upstream = 6/10 hour, time downstream therefore = 4/10 hour.distance traveled at 4km/hr in 6/10 hour = 24/10 = 2.4km.check: distance traveled at 6km/hr in 4/10 hour = 24/10 = 2.4km.