A train that is moving at a velocity of 8 m/s north begins a uniform acceleration of 0.05 m/s2 north. The acceleration is maintained through a distance of 800 m. What is the train's velocity after it has traveled the 800 m? How long does it take the train to travel the 800 m?

The answer is a) taiga because taigas are cold

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

Mass and velocity are the 2 factors used to calculate kinetic energy. the equation for kinetic energy is (1/2)mv^2. hope this !

I'd go with c) winter because that such a small angle. i think summer is 70-90, and autumn/spring are like 40-70.