Apile driver lifts a 450 kg weight and then lets it fall onto the end of a steel pipe that needs to be driven into the ground. a fall of 1.5 m drives the pipe in 45 cm.
what is the average force exerted on the pipe?

F = 14700N

Explanation:

Hello! Let's solve this!

We have the following data:

vi = 0m / s

dy = 1.5m

m = 450kg

dx = 0.45m

First we need to know the speed of the impeller.

We can use the following formula

We get the vf

vf = 4.42m / s

Then the kinetic energy is equal to the work done.

KE=1/2**450kg

We cleared KE

KE = W = 6615J

From the working formula we will clear the force exerted.

W = F * dx

F = W / dx = 6615J / 0.45m

F = 14700N

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm.   the wire diameter is d = 0.9 mm.   the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a                                          

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2)   in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

b.

hope this : )