A small section of a roller coaster consists of two hills and two dips. Three roller coaster cars (200 kg each) were lifted to the top of a hill that is 22 meters high. (a) How much work was done by the lift motor to get the cars to the top of the first hill (point B )?

(b) How much total mechanical energy does the car have at the top of the first hill (point B ) if it temporarily paused before it descends to point C ?

(c) What is the maximum speed that the coaster cars can attain at point C ?

(d) What is the net force on a 100 N passenger at point C ?

(e) What will be the net force on the same 100 N passenger at point D ?

(f) Will the cars maintain contact with the track at the top of the 14 meter tall second hill? Explain.

(g) What would be the minimum height of hill two (point D ) for the passenger in the cars to just maintain contact with the seat?

(h) What would be the g-force on the passenger at point D?

The answer is a i think

Answer///air resistance,drag;

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge