Suppose you drop a tennis ball from a height of 6 feet. after the ball hits the floor, it rebounds to 80% of
its previous height. how high will the ball rebound after its third bounce? round to the nearest tenth.

The height after the third bounce is 3.1 meters

Explanation: We know that after every bounce the ball rebounds to 80% (or 0.8 in decimal form) of its previous hight. So if the first height was 6m, after the first bounce, the height will be:

H1 = 6m*0.8 = 4.8m

after the second bounce we have:

H2 = 4.8m*0.8 = 3.84m

and in the third bounce, the height is:

H3 = 3.84m*0.8 = 3.072m

Now we need to round it to the nearest thenth, this is the first number after the decimal point.

We can see that the second number after the decimal point is a 7, so we should round up, and get H3 = 3.1m

Another way to model this situation is with the equation:

H(b) = 6m*0.8^b

Where b is the number of bounces that the ball did.

in this situation, the third bounce is when b= 3, and we have that:

H(3) = 6m*0,8^3 = 3.072m, which is the same result as before.

what experimental evidence led scientists to change from the previous model to this one?

a few of the positive particles aimed at a gold foil seemed to bounce back.

the colors of light emitted from heated atoms had very specific energies.

experiments with water vapor showed that elements combine in specific proportions.

cathode rays were bent in the same way whenever a magnet was brought near them.