A 2.75 kg block is pulled across a flat, frictionless floor with a 5.11 N force directed 53.8° above horizontal. What is the total force acting on the block? (total force = N)

F = 3.01 N

Explanation:

Given that,

Mass of a block, m = 2.75 kg

Force applied to the block, F = 5.11 N

It is directed 53.8° above horizontal.

We need to find the total force acting on the block. The force acting on it is given by :

So, 3.01 N of force is acting on the block.

into the screen

explanation:

the wind is hitting the car into the screen

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow