A 1 kg block with initial velocity 4 m/s collides elastically with a stationary 2 kg block. After the collision, the 1 kg block has a velocity of -1.33 m/s. Determine the speed of the 2 kg block after the collision.

  v₂ = 2,665 m / s

Explanation:

This is an exercise of conservation of the momentum, we define a system formed by the two cars, so that the forces during the collision are internal and the moment is conserved.

Initial instant. Before the crash

           p₀ = m v_o

Final moment. Right after the crash

           p_f = m v₁ + M v₂

where the first car uses subscript 1 and has a mass m = 1 kg and the second car uses the subscript 2 with a mass M = 2kg

how the moment is preserved

        p₀ = p_f

         m v_o = m v₁ + M v₂

They indicate that the collision is elastic, therefore the kinetic energy is conserved, the velocity of the first car is v1 = -1.33 me / S

         v₂ =

we calculate

        v₂ =

        v₂ = 2,665 m / s

answer: d. a cme increases the amount of energy in the solar wind

explanation:

coronal mass ejections, also called cmes, are large clouds of plasma and magnetic field that erupt from the sun. only when the cloud is aimed at earth will the cme hit earth and therefore cause impacts. high-speed solar wind streams come from areas on the sun known as coronal holes.

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