A 4kg object is moving at 5 m/s . A 10-N force is applied in the direction of motion and if the object has a final velocity 10m /s. calculate the distance that the object moves

Distance, S = 15m

Explanation:

Given the following data;

Mass = 4kg

Force = 10N

Initial velocity = 5m/s

Final velocity = 10m/s

To find the distance;

First of all, we would calculate the acceleration

Force = mass * acceleration

10 = 4*acceleration

Acceleration = 10/4

Acceleration = 2.5m/s²

Now to find the distance, we would use the third equation of motion.

Where;

V represents the final velocity measured in meter per seconds. U represents the initial velocity measured in meter per seconds. a represents acceleration measured in meters per seconds square.

S represents the displacement measured in meters.

Substituting into the equation, we have;

10² = 5² + 2*2.5*S

100 = 25 + 5S

5S = 100 - 25

5S = 75

Distance, S = 75/5

Distance, S = 15m

A) the moment of inertia is given by i = mr^2 here m = 0.25 and r = 0.5. i = 0.25 * (0.5)^2 = 0.0625. b) i = 9.74 * 10^(37) and mass = 5.98 * 10^(24) so r^2 = i/m = 9.74 * 10^(37)/5.98 * 10^(24) = 1.628 * 10^(37 - 24) = 1.628 * 10^(13) r = √ 1.628 * 10^(13) = 4034848.200 c) since angular momentum is the product of moment of inertia and angular velocity, a = i * v; but i = mr^2 = 2 * 0.6^2 = 0.72 so a = 0.72 * 1.1 = 0.792. if she pulls her hand in 0.15 m. the new radius = 0.6 - 0.15 = 0.45. v = angular momentum/ radius = 0.792/ 0.45 = 1.76

32 degrees celsius is 89.6 degrees fahrenheit so 50.22 degrees celsius are needed for it to be 212 degrees fahrenheit