Gladys wants to connect a 1 mH inductor to her computer clock (square wave) that has an off voltage of zero and an on voltage of 2.7 V. The clock runs at 1 GHz and has a 50% duty cycle (half on, half off). (a) Plot the current through the inductor for 10 ns. (b) If the inductor can handle a maximum current of 100 mA, how long until the maximum current is exceeded

This is the answer of your question

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j