Please please help me, don't guess please my test is timed !! A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.

1. Calculate the impulse delivered to the ball. (1pt)

2. What was the change in momentum of the ball? (1pt)

3. What was the velocity of the ball as it left the tennis racket? (1pt)

4. What would happen to the ball's velocity if it remained on the tennis racket longer than .05 s? (2pts)

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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