How high will a 1-kilogram ball go if it is thrown straight up into the air with an initial velocity of 30 m/sec?

h max = 45.92 m

Given

1 kg ball

vo=initial velocity = 30 m/s

Required

Height

Solution

We can use the principle of energy conservation or parabolic motion

For parabolic motion

h max = vo²sin²θ/2g(θ= 90° for straight up)

For conservation energy :

KE₁=PE₂

1/2.m.vo² = m.g.h

We choose parabolic motion

h max = vo²sin²θ/2g

h max = 30²sin²90/2 x 9.8

h max = 45.92 m

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