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Physics, 05.02.2021 01:00 grales65

PE = mgh KE = 2(mv^2)
ME = PE + KE
2.Suppose that ball is rolled down a bowling alley at a speed of 4.2 m/s, what is the kinetic energy of the ball?
energy of the ball?

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PE = mgh KE = 2(mv^2)
ME = PE + KE
2.Suppose that ball is rolled down a bowling alley a...
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