If King Kong fell straight down from the top of the Empire State Building (380m high), what is his velocity just before “landing”? a 0.00 m/s
b 86.3 m/s
c -86.3 m/s
d 38.7 m/s

86.3m/s

Explanation:

Given parameters:

Height  = 380m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we use one of the kinematic equations.

   V²   = U²  + 2gH

V is the final velocity

U is the initial velocity  = 0m/s

g is the acceleration due to gravity

H is the height

           V²   = 0²  +    (2 x 9.8 x 380) = 7448

          V = 86.3m/s

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.