25.0 g of mercury is heated from 25°C to 155°C, and absorbs 455 joules of heat in the process Calculate the specific heat capacity of mercury.

0.048J/g°C

Explanation:

Given parameters:

Mass of Mercury  = 25g

Initial temperature  = 25°C

Final temperature  = 155°C

Amount of heat absorbed  = 455J

Unknown:

Specific heat capacity of mercury  = ?

Solution:

To solve this problem, we use the expression below:

      Q  = m x C  x Δt

Q is the heat absorbed

m is the mass

C is the unknown specific heat capacity

Δt is the change in temperature;

          455  = 25 x C x (155  - 25)

          455  = 25 x C x 130

             C  = 0.048J/g°C

be subject to a force andchange its motion

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge