What mass of ice at -14°C will be needed to cool 200cm^3 of an orange drink(essentially water) from 25°C. to 10°C. (Specific Latent heat of Fusion of ice= 3.36 ×10^5 J/Kg
Specific heat capacity of ice =2100 J/kg/k
specific heat capacity of water=4200J/Kg/k) ?

Please show workings.

  31 grams

Explanation:

The amount of heat required to raise a mass (m, in kg) of ice from -14 °C to 10 °C is ...

  heat to raise temperature of ice to 0 °C:

     (2100 J/kg/K)(m kg)(14 K) = (29400m) J

  heat to melt ice:

     (336000 J/kg)(m kg) = (336000m) J

  heat to raise melted ice to 10 °C

     (4200 J/kg/K)(m kg)(10 K) = (42000m) J

So, the total heat required to raise m kg of ice from -14 °C to +10 °C is ...

  (29,400 + 336,000 + 42,000)m J = (407400m) J

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The heat required to cool 200 cc = 200 g = 0.2 kg of drink by 15 K is ...

  (4200 J/kg/K)(0.20 kg)(15 K) = 12600J

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The minimum amount of ice will be used if it all melts, so the two quantities of heat are the same:

  407400m = 12600 . . . . joules

  m = 12600/407400 ≈ 0.030928 . . . . kg

About 31 grams of ice are needed.

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.