Two identical cars capable of accelerating at 3.00 m/s² are racing on a straight track with running
starts. Car A has an initial speed of 2.50 m/s ; car B
starts with speed of 4.10 m/s.
Part A
What is the separation of the two cars after 10 s?

because growing process had stoped after 4-5 year

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it