A projectile is launched with an initial velocity 60m/s at an angle 60° to the vertical. What the magnitude of it's displacement after 5s.

the magnitude of the displacement after 5s is 137.31 m.

Explanation:

Given;

initial velocity of the projectile, u = 60 m/s

angle of projection, θ = 60°

time of motion, t = 5s

the vertical component of the velocity,

The magnitude of the displacement after 5s is calculated as;

Therefore, the magnitude of the displacement after 5s is 137.31 m.

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