If the man has an initial velocity of 0.4 m/s with a time of 5.8 seconds and an experimental displacement of 8.167 meters and acceleration of 0.343 m/s^2, what is his calculated displacement? Group of answer choices

7.98 m

7.62 m

8.99 m

8.09 m

8.09

Explanation:

Use: s = ut + 1/2at^2

s = displacement

u = initial velocity

a = acceleration

t = time

Plug in numbers and get: 8.09

c. newton's third law of motion

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.