A block with a mass of 5.0 kg is pushed on a frictionless surface through a distance of 5.0 m by applying a horizontal force of 80.0 N. Hint: Use Newton's 2nd Law to find the acceleration first
Applied
Force = 80.0 N
m = 5.0 kg
5.0 m
If the block starts from rest, what is its final velocity?
А
B
8.9 m/s
12.6 m/s
16.0 m/s
с
D
31.6 m/s

The force will determine the acceleration.

On a horizontal frictionless surface, a small block with mass 0.200 kg has a collision with a block of mass 0.400 kg. immediately after the collision, the 0.200 kg block is moving at 12.0 m/s in the direction 30° north of east and the 0.400 kg block is moving at 11.2 m/s in the direction 53.1° south of east. use coordinates where the +x-axis is east and the +y-axis is north.(a) what is the total kinetic energy of the two blocks after the collision (in ) what is the x-component of the total momentum of the two blocks after the collision? (indicate the direction with the sign of your ) what is the y-component of the total momentum of the two blocks after the collision? (indicate the direction with the sign of your answer.)

Atemperature inversion can cause a warm air mass to move over a colder air mass. this traps the colder air mass and prevents surface air from rising. this may result in which of these? a) smog b) acid rain c) freezing rain d) a thunderstorm