14. A 2.5 kg object is experiencing a net force of 50 N while traveling in a circle at a velocity of 5.0 m/s. What is the radius of its motion?

1.25 meters

Explanation:

Given data

Mass= 2.5kg

Force= 50N

velocity= 5m/s

r=

Applying the formula

F= mv^2/r

Make r subject of formula

r= mv^2/F

r= 2.5*5^2/50

r= 2.5*25/50

r=62.5/50

r=1.25 meters

Hence the radius is 1.25 meters

cell differentiation  is how generic embryonic  cells  become specialized  cells. this occurs  through a process called gene expression. gene expression is the specific combination of genes that are turned on or off (expressed or repressed), and this is what dictates how a  cell  functions.

explanation: