6. The figure shows a student pushing a 1.22 kg box across a frictionless floor a distance of 5.0 m by applying a force of 30.0 N.
What is the work done on the box by the two forces, Fn and Fa , as it
is pushed 5.0 m along the floor?
F = 12.0 N
F=30.0 N
5 m
A. Work by Fn = 0 Joules Work by Fa = 0 Joules
B. Work by Fn = 0 Joules Work by Fa = 150 Joules
C. Work by Fn = 60 Joules Work by Fa = 0 Joules
D. Work by Fn = 60 Joules Work by Fa = 150 Joules

the design of a ski jumping suit involves a trade-off between giving the skiers lift to get higher jumps and ensuring the skier does not face a lot of drag before the jump itself. an expansive suit may to lift the skier higher, but at the same time, it will also increase the air resistance. higher air resistance as the skier goes down the slope limits the speed of the jump. a big suit also increases the risk of losing balance or control, especially if there's a strong gust of wind. while technologically enhanced suits a lot, clothing is not the only factor in a ski jumper’s success. gathering speed while skiing down the slope, ensuring good speed on the ramp, and maintaining good body posture and form in the air all contribute to a ski jumper's success.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m