Two cars, a Porsche Boxster convertible and a Toyota Scion xB, are traveling at constant speeds in the same direction. Suppose, instead, that the Boxster is initially 170 m behind the Scion. The speed of the Boxster is 24.4 m/s and the speed of the Scion is 18.6 m/s. How much time does it take for the Boxster to catch the Scion

It will take 29.31 seconds for the Boxster to catch the Scion

Explanation:

Given the data in the question;

lets say Toyota Scion xB is car A and Porsche Boxster convertible is B and Toyota Scion xB is car A

the distance travelled by car A is

x = × t

where   is the speed of the car and t is time

the distance travelled by car B before reaching car A will be;

x + x₀ = × t

Now lets replace x by × t

so

( × t) + x₀ = × t

x₀ = ( × t) - ( × t)

x₀ = t ( - )

t = x₀ /  ( - )

so we substitute

t = 170 m  /  (24.4 - 18.6)  

t = 170 / 5.8

t = 29.31 s

Therefore; it will take 29.31 s for the Boxster to catch the Scion

3.2x10^7

the force on the thing and the distance the force moves the thing