a light bulb with a resistance of 2.0 ohms is connected to a 1.5 v battery. what is the current in the circuit?

Taking into account the Ohm's Law, the current in the circuit is 0.75 amperes.

The basic relationships of the intensity of the current, voltage and resistance are as follows:

The current intensity of a circuit increases when the voltage is increased without varying the resistance. The current intensity of a circuit decreases when resistance is increased without varying the voltage.

These two relationships constitute Ohm's Law. So, Ohm's law is the relationship between electrical conductors and their resistance, which establishes that the current that passes through the conductors is proportional to the voltage applied to them.

Ohm's law expressed mathematically is:

V = R×I

where:

V is the electric potential in voltsI is the current in amperesR is the resistance in ohms.

In this case, you know:

V= 1.5 voltsR= 2 ohmsI= ?

Replacing:

1.5 volts= 2 ohms* I

Solving:

I= 1.5 volts ÷2 ohms

I= 0.75 amperes

In summary, the current in the circuit is 0.75 amperes.

Learn more about Ohm's law:

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Explanation:

I= V/R V = 1.5v R = 2 ohm I =1.5/2 = 1.5×10/2×10 =15 / 20 =3/4 I = 0.75 A

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