A 8.0-kg ball is thrown towards a wall with a speed of 9.0 m/s. The ball hits the wall and rebounds backward with a speed of 2.0 m/s. What is the momentum change experienced by the ball?

DP = 56 [kg*m/s]

Explanation:

We know that momentum is defined by the product of mass by Velocity. In this way by means of the following equation, we can calculate the impulse.

where:

P = momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

Now replacing:

And after the ball hits the wall:

The change in momentum is equal to:

answer: the exterior temperature of commercial jet planes as they leave the stratosphere and return to the ground increases steadily.

explanation:

the lower most layer of atmosphere is troposphere which extends from 0 to 12 km above the surface of the earth. the temperature initially decreases as distance is increased from the earth's surface. commercial jets fly in lower part of the stratosphere. the stratosphere extends upto 50 km. the temperature in stratosphere starts rising again due to presence of ozone which traps the uv rays.

thus, when the planes leave the stratosphere and return to the ground, the exterior temperature increases steadily.