A resistor of 3.6ohms is connected in seris with another of 4.56ohms. What resistance must be placed across 3.6ohms so that total resistance of the circuit shall be 6ohms

Explanation:

Let the resistance placed across the 3.6ohms be x, this means that they are both connected in parallel and then in series to 4.56 ohms;

The equivalent resistance is expressed as;

RT = (1/3.6+1/x) + 4.56

RT = 3.6x/3.6+x + 4.56

Since RT = 6ohms

6 = 3.6x/3.6+x + 4.56

6 - 4.56 = 3.6x/3.6+x

1.44= 3.6x/3.6+x

1.44(3.6+x) = 3.6x

5.184+ 1.44x = 3.6x

5.184 = 3.66x - 1.44x

5.184 = 2.22x

x = 5.184/2.22

x = 2.34  ohms

Hence the resistance that must be placed across 3.6ohms so that total resistance of the circuit shall be 6ohms is 2.34 ohms

measure their densities same density, same sub

see earlier