1) In the early morning, a park ranger in a canoe is observing wildlife on the nearby shore. Earth's gravitational force on the ranger is 760 N downward, and its gravitational force on the boat is 190 N downward. The water
keeps the canoe afloat by exerting a 950 N force upward on it. Draw a free-body diagram of the canoe.

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

They all deal with hard evidence(scientific)

The answer would be d. hope this :

Cannot be determined because i dont  know this but i need the points