A force of 62 N acts on a 35 kg object for 10.0s. What is the objects change in momentum?

Δp = 620 N.s

Explanation:

Newton's second law, was originally conceived  as follows:

       

In this way, a net force applied on an object, is equal to the rate of change of the momentum of the object regarding time.

       for m= constant, it reduces to F= m*a.

Replacing in (1) F= 62 N, and Δt = 10.0 s, we can solve for Δp (object's change in momentum) , as follows:

       

No because scientist are still changing there mines today so they are not correct to this day

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge