Coulomb's Law: Coulomb's law is F = k (q1xq2)/ r^2 where k = 9 x 10^9 C^2/m^2. a) Sketch the charges and use Coulomb's law to determine the electric force between two charged particles where q1 = -5 x 10^-3 C and q2 = -1 x 10^-3 C. Q1 and Q2 are separated by a distance of 0.25 m. b) Determine whether the electric force attractive or repulsive and explain your answer?

a) F = 7.20 10⁵ N,  b) the force between charges is repulsive.

Explanation:

For this exercise we calculate the electric forces given by Coulomb's law

where in this case they indicate that q1 = 5 103 C and q2 = 1 103 C and the distance between them r = 0.25 m

let's calculate

                  F =

                  F = 7.20 10⁵ N

b) when electric charges have the same sign they repel and when they have the opposite sign they attract.

In this case, charge 1 is negative and charge 2 is negative, therefore, since they both have the same sign, the force between charges is repulsive.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..