A 55.0 Kg crate is to be accelerated at 8.00 m/s up an inclined plane making a 35° angle with the horizontal. If the coefficient of friction is 0.200, how much force is required?

I'll do it rn and then answer

Make them both to where they have the denominator of 18that makes 3/2 equal 27/18 and 1/9 equal 2/18so now you have  27/18x+5=2/18subtract 5 from the other sideso now you have 27/18x+2/18-5then subtract 2/18 from 27/18 to get 25/18x=-5then divide 25/18 by -5 and your answer will be  -5/18

There's nothing  on the list you provided to which that law applies.