Abasket has a mass of 5.5 kg. find the magnitude of the normal force if the basket is at rest on a ramp inclined above the horizontal at:

a) 0 degrees (horizontal surface)
b) 12 degrees
c) 25 degrees
d) 45 degrees

can you write the answer and the steps how you found the magnitude

(a) 53.9 N

(b) 52.72 N

(c) 48.85 N

(d) 38.11 N

Explanation:

The normal force is always perpendicular to the surface.

(a) the normal force = m x g = 5.5 x 9.8 = 53.9 N

(b) Normal force = m x g x CosФ = 5.5 x 9.8 x Cos 12 = 52.72 N

(c) Normal force = m x g x CosФ = 5.5 x 9.8 x Cos 25 = 48.85 N

(d) Normal force = m x g x CosФ = 5.5 x 9.8 x Cos 45 = 38.11 N

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm