A 60 kg swimmer suddenly dives from a 150 kg raft with a speed of 1.5 m/s. The raft is initially at rest. What is the speed of the raft immediately after the diver jumps if the water has negligible
effect on the raft?

v2 = 0.6 m/s in opposite direction

Explanation:

The computation of the speed of the raft is as follows

The center of system mass would be remains at the same place also it has no external force applied

Therefore

V = 0

So,  

M1.V1= - (M2.V2)

where,

M1 = 60 kg, V1 = 1.5 m/s

M2 = 150 kg

Now  

60 × 1.5 = - 150 × v2

v2 = -0.6 m/s

v2 = 0.6 m/s in opposite direction

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

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