100 point question!! A driver begins to brake when her car is traveling at 15.0 m/s, and the car comes to a stop 4.0 s later. How much farther does the car go after the driver begins to brake, assuming constant acceleration?

30 m

Explanation:

Let's list out the known variables that we are given in this question.

We are trying to solve for displacement in the x-direction.

Find which constant acceleration equation contains all 4 of these variables.

Plug the known values into the equation and solve for delta x.

The car goes 30 m after the driver begins to brake.

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.